# highest oxidation state is achieved by which of the following?

Example $$\PageIndex{4}$$: This is the reaction between magnesium and hydrogen chloride: $\ce{Mg + 2HCl -> MgCl2 +H2} \nonumber$ Solution. The highest oxidation state is shown by chlorine in which of the following oxide ? Oxidation states are typically represented by integers, which can be positive, negative, or zero. MEDIUM. Vanadium has oxidation states in its compounds of +5, +4, +3 and +2. Biology. | EduRev NEET Question is disucussed on … (ii) Co 2+ is easily oxidised in the presence of a strong ligand. The elctronic configuration of Manganese is. So once again, it makes sense. Ask your question. The Highest Oxidation state is that of 1. Metal exhibiting highest oxidation state belongs to 1) p-block 2) f-block 3) S-block 4)d-block 4 Among the following outermost configuration of metals, the highest oxidation state achieved by 1) 3d3 4s2 2) 3d5 4s1 3) 3d5 4s2 4) 3d6 4s2 5. Of the following outer electronic configurations of atoms, the highest oxidation state is achieved by which one of them? Of the following outer electronic configurations of atoms, the highest oxidation state is achieved by which one of them [AIEEE 2004] A) $(n-1){{d}^{3}}n{{s}^{2}}$ done clear Answer: Manganese is the 3d series transition element shows the highest oxidation state. Observing the changes in the lab Xenon All Show +8 oxidation state (among many other states). Reduction involves a decrease in oxidation state; In each of the following examples, we have to decide whether the reaction is a redox reaction, and if so, which species have been oxidized and which have been reduced. NCERT RD Sharma Cengage KC Sinha. Assign each element its oxidation … \mathrm{NaNO}_{2} The Study-to-Win Winning Ticket number has been announced! Of the following outer electronic configurations of atoms, the highest oxidation state is achieved by which one of them? 4.1k VIEWS \begin{array}{lll}{\text { a. }} (iii) fluorine stabilises lower oxidation state. Which of the following electronic configuration is associated with the highest stable oxidation state? Physics. 1.Order the following molecules from highest oxidation state to lowest oxidation state - methanol, carbonic acid, formaldehyde, methane. Figure 1: Oxidation … Download PDF's. }+7} & {\text { c… Enroll in one of our FREE online STEM bootcamps. NCERT RD Sharma Cengage KC Sinha. Join Now. Highest oxidation state of manganese in fluoride is +4 (MnF 4) but highest oxidation state in oxides is +7 (Mn 2 O 7) because _____. Can you explain this answer? Ask for details ; Follow Report by Sdsheikahamed 15.12.2019 Log in to add a comment NCERT P Bahadur IIT-JEE Previous Year Narendra Awasthi MS Chauhan. MEDIUM. (a) (n-1)d 8 ns 2 (b) (n-1)d 5 ns 1 (c) (n-1)d 3 ns 2 (d) (n-1)d 5 ns 2. Basically their respective Tetroxides do. View Answer From the below-given pairs, w hich is more stable? Oxidation increases oxidation state and reduction decreases oxidation state. 196 Views. NO2, NaNO2, N2O, HNO3, and NH4Cl. D [A r] 3 d 6 4 s 2. Carbon has 9!! Click hereto get an answer to your question ️ Of the following outer electronic configurations of atoms, the highest oxidation state is achieved by which one of them? (n-1)d 5 ns 2. (i) The highest oxidation state of a transition metal is usually exhibited in its oxide. So, oxo-anions of metal have the highest oxidation state. ← Prev Question Next Question → +1 vote . Of the following outer electronic configurations of atoms,the highest oxidation state is achieved by which one of them So the net oxidation for this part of the molecule or the compound is going to be negative 2 nets out with the positive 2 from magnesium. Of the following outer electronic configurations of atoms, the highest oxidation state is achieved by which one of them? Physics. The reason why Manganese has the highest oxidation state is because the number of unpaired electrons in the outermost shell is more that is 3d 5 4s 2.. See Periodic Table below: In the image above, the blue-boxed area is the d block, or also known as transition metals. A $$(\mathrm{n}-1)\mathrm{d}^{8}\mathrm{n}\mathrm{s}^{2}$$ Hope you found this question and answer to be good. (ii) fluorine does not possess d-orbitals. Class 12 Class 11 … (a) (n – 1)d³ ns² (b) (n – 1)d⁵ ns¹ (c) (n – 1)d⁸ ns² (d) (n – 1)d⁵ ns² Ask for details ; Follow Report by Sivarenuka9181 17.03.2019 Log in to add a comment What do you need to know? Maths. Pick the true statement amongst the following. Of the following outer electronic configurations of atoms, the highest oxidation state is achieved by which one of them? Question 8. ⇐ Oxidation Number Calculator . Biology. B. View Winning Ticket Chemistry. I tried several answers, but they are all wrong. NCERT P Bahadur IIT-JEE Previous Year Narendra Awasthi MS Chauhan. NCERT DC Pandey Sunil Batra HC Verma Pradeep Errorless. The oxidation state of Iodine in Diiodine Monoxide(I 2 O) is +1, in Iodine Monoxide(IO) it is +2, in Iodine Dioxide(IO 2) it is +4, in Diiodine Tetroxide((IO 2) 2) it is +3 and +5, in Diiodine Pentoxide(O(IO 2) 2) it is +5 and in tetraiodine nonoxide(I(OIO 2) 3) it is +3 and +5. Nov 23,2020 - Of the following outer electronic configurations of atoms, the highest oxidation state is achieved by which one of them?a)3ds4s1b)3ds4s2c)3d34s2d)3d64s2Correct answer is option 'D'. Each hydroxide part of this molecule is going to have a net oxidation state of negative 1. Osmium 2. Structure of Atom. 89 views. The maximum oxidation state shown by the elements of first transition series increases from Sc to Mn and then decreases to Zn. (i) fluorine is more electronegative than oxygen. C [A r] 3 d 5 4 s 2. View Answer. Many of the reactions that organic molecules undergo involve changes in the oxidation level of one or more carbon atoms within the compound. In the highest oxidation states of the first five transition elements (Sc to Mn), all the 4s and 3d electrons are used for bonding. The common oxidation states of transition and inner transition elements are respectively 1) +2,+2 2)+3, +2 3)+2, +3 4)+3,+3 6. Join today and start acing your classes!View Bootcamps. (ii) Cr 2+ is a strong reducing agent. Oxidation state indicates the degree of oxidation for an atom in a chemical compound; it is the hypothetical charge that an atom would have if all bonds to atoms of different elements were completely ionic. Login.